Electrolytes & minerals

Iodine (serum): convert µg/L to nmol/L

nmol/L = µg/L × 7.88

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µg/L nmol/L

µg/L → nmol/L	nmol/L = µg/L × 7.88
nmol/L → µg/L	µg/L = nmol/L × 0.1269

Source: PubChem: periodic table element data · Last reviewed: 2026-10-19

How do I convert Iodine (serum) from µg/L to nmol/L?

nmol/L = µg/L × 7.88. For example, 10 µg/L equals 78.8 nmol/L.

How many nmol/L are 10 µg/L?

10 µg/L equal 78.8 nmol/L (Iodine (serum)).

How do I convert Iodine (serum) from nmol/L back to µg/L?

µg/L = nmol/L × 0.1269.